Base | Representation |
---|---|
bin | 10111001100110100… |
… | …01011000110101111 |
3 | 1012011001022210000111 |
4 | 23212122023012233 |
5 | 201002110234003 |
6 | 5415541440451 |
7 | 620442321616 |
oct | 134632130657 |
9 | 35131283014 |
10 | 12455555503 |
11 | 5311922226 |
12 | 24b7410127 |
13 | 12366580b1 |
14 | 86232487d |
15 | 4cd759e6d |
hex | 2e668b1af |
12455555503 has 4 divisors (see below), whose sum is σ = 12857347648. Its totient is φ = 12053763360.
The previous prime is 12455555473. The next prime is 12455555509. The reversal of 12455555503 is 30555555421.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30555555421 = 17 ⋅1797385613.
It is a cyclic number.
It is not a de Polignac number, because 12455555503 - 217 = 12455424431 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12455555509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200896026 + ... + 200896087.
It is an arithmetic number, because the mean of its divisors is an integer number (3214336912).
Almost surely, 212455555503 is an apocalyptic number.
12455555503 is a deficient number, since it is larger than the sum of its proper divisors (401792145).
12455555503 is an equidigital number, since it uses as much as digits as its factorization.
12455555503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 401792144.
The product of its (nonzero) digits is 375000, while the sum is 40.
The spelling of 12455555503 in words is "twelve billion, four hundred fifty-five million, five hundred fifty-five thousand, five hundred three".
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