Base | Representation |
---|---|
bin | 111010000111011100… |
… | …1011110100100011111 |
3 | 102221010210202002122112 |
4 | 1310032321132210133 |
5 | 4021044311000111 |
6 | 133200102504235 |
7 | 12005521332254 |
oct | 1641671364437 |
9 | 387123662575 |
10 | 124804000031 |
11 | 48a24671487 |
12 | 2023073507b |
13 | b9cc55c539 |
14 | 607d38742b |
15 | 33a6ae2e8b |
hex | 1d0ee5e91f |
124804000031 has 2 divisors, whose sum is σ = 124804000032. Its totient is φ = 124804000030.
The previous prime is 124803999919. The next prime is 124804000099. The reversal of 124804000031 is 130000408421.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124804000031 is a prime.
It is a super-2 number, since 2×1248040000312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124803999970 and 124804000006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124804000231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62402000015 + 62402000016.
It is an arithmetic number, because the mean of its divisors is an integer number (62402000016).
Almost surely, 2124804000031 is an apocalyptic number.
124804000031 is a deficient number, since it is larger than the sum of its proper divisors (1).
124804000031 is an equidigital number, since it uses as much as digits as its factorization.
124804000031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 124804000031 its reverse (130000408421), we get a palindrome (254804408452).
The spelling of 124804000031 in words is "one hundred twenty-four billion, eight hundred four million, thirty-one", and thus it is an aban number.
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