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124949000447 is a prime number
BaseRepresentation
bin111010001011110001…
…0100111000011111111
3102221111220120212211022
41310113202213003333
54021343421003242
6133222322414355
712012231660065
oct1642742470377
9387456525738
10124949000447
1148a994a9437
12202712013bb
13ba235ca8bb
146094730035
1533b46d60d2
hex1d178a70ff

124949000447 has 2 divisors, whose sum is σ = 124949000448. Its totient is φ = 124949000446.

The previous prime is 124949000413. The next prime is 124949000461. The reversal of 124949000447 is 744000949421.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 124949000447 - 218 = 124948738303 is a prime.

It is a super-2 number, since 2×1249490004472 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 124949000398 and 124949000407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124949000047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62474500223 + 62474500224.

It is an arithmetic number, because the mean of its divisors is an integer number (62474500224).

Almost surely, 2124949000447 is an apocalyptic number.

124949000447 is a deficient number, since it is larger than the sum of its proper divisors (1).

124949000447 is an equidigital number, since it uses as much as digits as its factorization.

124949000447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 290304, while the sum is 44.

Adding to 124949000447 its reverse (744000949421), we get a palindrome (868949949868).

The spelling of 124949000447 in words is "one hundred twenty-four billion, nine hundred forty-nine million, four hundred forty-seven", and thus it is an aban number.