Base | Representation |
---|---|
bin | 111010001011110001… |
… | …0100111000011111111 |
3 | 102221111220120212211022 |
4 | 1310113202213003333 |
5 | 4021343421003242 |
6 | 133222322414355 |
7 | 12012231660065 |
oct | 1642742470377 |
9 | 387456525738 |
10 | 124949000447 |
11 | 48a994a9437 |
12 | 202712013bb |
13 | ba235ca8bb |
14 | 6094730035 |
15 | 33b46d60d2 |
hex | 1d178a70ff |
124949000447 has 2 divisors, whose sum is σ = 124949000448. Its totient is φ = 124949000446.
The previous prime is 124949000413. The next prime is 124949000461. The reversal of 124949000447 is 744000949421.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124949000447 - 218 = 124948738303 is a prime.
It is a super-2 number, since 2×1249490004472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 124949000398 and 124949000407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124949000047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62474500223 + 62474500224.
It is an arithmetic number, because the mean of its divisors is an integer number (62474500224).
Almost surely, 2124949000447 is an apocalyptic number.
124949000447 is a deficient number, since it is larger than the sum of its proper divisors (1).
124949000447 is an equidigital number, since it uses as much as digits as its factorization.
124949000447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 290304, while the sum is 44.
Adding to 124949000447 its reverse (744000949421), we get a palindrome (868949949868).
The spelling of 124949000447 in words is "one hundred twenty-four billion, nine hundred forty-nine million, four hundred forty-seven", and thus it is an aban number.
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