Base | Representation |
---|---|
bin | 111010001101010010… |
… | …1001010001000000011 |
3 | 102221122110112221001202 |
4 | 1310122211022020003 |
5 | 4022000000000003 |
6 | 133231343451415 |
7 | 12013421316614 |
oct | 1643245121003 |
9 | 387573487052 |
10 | 125000000003 |
11 | 4901527212a |
12 | 202862b6b6b |
13 | ba31045c58 |
14 | 609b407c0b |
15 | 33b8e0c088 |
hex | 1d1a94a203 |
125000000003 has 2 divisors, whose sum is σ = 125000000004. Its totient is φ = 125000000002.
The previous prime is 124999999997. The next prime is 125000000039. The reversal of 125000000003 is 300000000521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125000000003 - 210 = 124999998979 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (125000000093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62500000001 + 62500000002.
It is an arithmetic number, because the mean of its divisors is an integer number (62500000002).
Almost surely, 2125000000003 is an apocalyptic number.
125000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
125000000003 is an equidigital number, since it uses as much as digits as its factorization.
125000000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30, while the sum is 11.
Adding to 125000000003 its reverse (300000000521), we get a palindrome (425000000524).
The spelling of 125000000003 in words is "one hundred twenty-five billion, three", and thus it is an aban number.
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