Base | Representation |
---|---|
bin | 10111010010001000… |
… | …01111101101110111 |
3 | 1012021011012211220100 |
4 | 23221010033231313 |
5 | 201100013420441 |
6 | 5424213205143 |
7 | 621523266363 |
oct | 135104175567 |
9 | 35234184810 |
10 | 12500138871 |
11 | 5335003390 |
12 | 250a3307b3 |
13 | 1242967b9c |
14 | 86820c2a3 |
15 | 4d2614cb6 |
hex | 2e910fb77 |
12500138871 has 12 divisors (see below), whose sum is σ = 19697188680. Its totient is φ = 7575841680.
The previous prime is 12500138863. The next prime is 12500138891. The reversal of 12500138871 is 17883100521.
12500138871 is a `hidden beast` number, since 1 + 2 + 500 + 1 + 3 + 88 + 71 = 666.
It is not a de Polignac number, because 12500138871 - 23 = 12500138863 is a prime.
It is a super-3 number, since 3×125001388713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12500138891) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 63131916 + ... + 63132113.
It is an arithmetic number, because the mean of its divisors is an integer number (1641432390).
Almost surely, 212500138871 is an apocalyptic number.
12500138871 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
12500138871 is a deficient number, since it is larger than the sum of its proper divisors (7197049809).
12500138871 is a wasteful number, since it uses less digits than its factorization.
12500138871 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126264046 (or 126264043 counting only the distinct ones).
The product of its (nonzero) digits is 13440, while the sum is 36.
It can be divided in two parts, 1250013 and 8871, that added together give a square (1258884 = 11222).
The spelling of 12500138871 in words is "twelve billion, five hundred million, one hundred thirty-eight thousand, eight hundred seventy-one".
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