Base | Representation |
---|---|
bin | 1011010111100111101010… |
… | …0011110100001000110111 |
3 | 1122021000202010201211100012 |
4 | 2311321322203310020313 |
5 | 3114301320211242221 |
6 | 42330335355210435 |
7 | 2430060560455205 |
oct | 265717243641067 |
9 | 48230663654305 |
10 | 12500411040311 |
11 | 3a8a438168a37 |
12 | 149a7b6446a1b |
13 | 6c8a25a4617c |
14 | 31304763c075 |
15 | 16a26eb9865b |
hex | b5e7a8f4237 |
12500411040311 has 2 divisors, whose sum is σ = 12500411040312. Its totient is φ = 12500411040310.
The previous prime is 12500411040281. The next prime is 12500411040323. The reversal of 12500411040311 is 11304011400521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12500411040311 - 210 = 12500411039287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12500411040331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250205520155 + 6250205520156.
It is an arithmetic number, because the mean of its divisors is an integer number (6250205520156).
Almost surely, 212500411040311 is an apocalyptic number.
12500411040311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12500411040311 is an equidigital number, since it uses as much as digits as its factorization.
12500411040311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 12500411040311 its reverse (11304011400521), we get a palindrome (23804422440832).
The spelling of 12500411040311 in words is "twelve trillion, five hundred billion, four hundred eleven million, forty thousand, three hundred eleven".
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