125011301 has 2 divisors, whose sum is σ = 125011302. Its totient is φ = 125011300.

The previous prime is 125011297. The next prime is 125011331. The reversal of 125011301 is 103110521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75238276 + 49773025 = 8674^2 + 7055^2 .

It is a cyclic number.

It is not a de Polignac number, because 125011301 - 2² = 125011297 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125011331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62505650 + 62505651.

It is an arithmetic number, because the mean of its divisors is an integer number (62505651).

Almost surely, 2^125011301 is an apocalyptic number.

It is an amenable number.

125011301 is a deficient number, since it is larger than the sum of its proper divisors (1).

125011301 is an equidigital number, since it uses as much as digits as its factorization.

125011301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 125011301 is about 11180.8452721608. The cubic root of 125011301 is about 500.0150675459.

Adding to 125011301 its reverse (103110521), we get a palindrome (228121822).

The spelling of 125011301 in words is "one hundred twenty-five million, eleven thousand, three hundred one".