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12501132433 = 293317134593
BaseRepresentation
bin10111010010010000…
…00010010010010001
31012021020002022210221
423221020002102101
5201100242214213
65424250353041
7621534605146
oct135110022221
935236068727
1012501132433
115335621909
12250a72b781
131242c251aa
148683ca3cd
154d275e38d
hex2e9202491

12501132433 has 8 divisors (see below), whose sum is σ = 12583462248. Its totient is φ = 12419073024.

The previous prime is 12501132409. The next prime is 12501132443. The reversal of 12501132433 is 33423110521.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 670654609 + 11830477824 = 25897^2 + 108768^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12501132433 - 25 = 12501132401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12501132398 and 12501132407.

It is not an unprimeable number, because it can be changed into a prime (12501132443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25585 + ... + 160177.

It is an arithmetic number, because the mean of its divisors is an integer number (1572932781).

Almost surely, 212501132433 is an apocalyptic number.

It is an amenable number.

12501132433 is a deficient number, since it is larger than the sum of its proper divisors (82329815).

12501132433 is a wasteful number, since it uses less digits than its factorization.

12501132433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135203.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 12501132433 its reverse (33423110521), we get a palindrome (45924242954).

The spelling of 12501132433 in words is "twelve billion, five hundred one million, one hundred thirty-two thousand, four hundred thirty-three".

Divisors: 1 293 317 92881 134593 39435749 42665981 12501132433