Base | Representation |
---|---|
bin | 111010001110010000… |
… | …1010001010110001001 |
3 | 102221201201202220021200 |
4 | 1310130201101112021 |
5 | 4022031312113213 |
6 | 133234505054413 |
7 | 12014265005241 |
oct | 1643441212611 |
9 | 387651686250 |
10 | 125032535433 |
11 | 49031674513 |
12 | 20295187409 |
13 | ba379c7ca0 |
14 | 60a1876b21 |
15 | 33bbbd7273 |
hex | 1d1c851589 |
125032535433 has 24 divisors (see below), whose sum is σ = 196383375552. Its totient is φ = 76196071008.
The previous prime is 125032535371. The next prime is 125032535477. The reversal of 125032535433 is 334535230521.
125032535433 is a `hidden beast` number, since 1 + 2 + 50 + 32 + 535 + 43 + 3 = 666.
It is not a de Polignac number, because 125032535433 - 220 = 125031486857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125032535333) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5175591 + ... + 5199692.
It is an arithmetic number, because the mean of its divisors is an integer number (8182640648).
Almost surely, 2125032535433 is an apocalyptic number.
125032535433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
125032535433 is a deficient number, since it is larger than the sum of its proper divisors (71350840119).
125032535433 is a wasteful number, since it uses less digits than its factorization.
125032535433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10375405 (or 10375402 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 36.
Adding to 125032535433 its reverse (334535230521), we get a palindrome (459567765954).
The spelling of 125032535433 in words is "one hundred twenty-five billion, thirty-two million, five hundred thirty-five thousand, four hundred thirty-three".
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