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12504314323 is a prime number
BaseRepresentation
bin10111010010101000…
…01011000111010011
31012021110001222112201
423221110023013103
5201102101024243
65424442504031
7621603626614
oct135124130723
935243058481
1012504314323
1153373a5476
12250b805017
13124379a577
148689b7c0b
154d2b8c04d
hex2e950b1d3

12504314323 has 2 divisors, whose sum is σ = 12504314324. Its totient is φ = 12504314322.

The previous prime is 12504314269. The next prime is 12504314359. The reversal of 12504314323 is 32341340521.

It is a happy number.

12504314323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12504314323 - 221 = 12502217171 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12504314291 and 12504314300.

It is not a weakly prime, because it can be changed into another prime (12504314023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252157161 + 6252157162.

It is an arithmetic number, because the mean of its divisors is an integer number (6252157162).

Almost surely, 212504314323 is an apocalyptic number.

12504314323 is a deficient number, since it is larger than the sum of its proper divisors (1).

12504314323 is an equidigital number, since it uses as much as digits as its factorization.

12504314323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 12504314323 its reverse (32341340521), we get a palindrome (44845654844).

The spelling of 12504314323 in words is "twelve billion, five hundred four million, three hundred fourteen thousand, three hundred twenty-three".