Base | Representation |
---|---|
bin | 111010001110100110… |
… | …1000110011110101111 |
3 | 102221202112101122100221 |
4 | 1310131031012132233 |
5 | 4022042232302023 |
6 | 133235555232211 |
7 | 12014464451263 |
oct | 1643515063657 |
9 | 387675348327 |
10 | 125044025263 |
11 | 49038101a43 |
12 | 20298ba8667 |
13 | ba3a1bb9c1 |
14 | 60a31c80a3 |
15 | 33bcc0685d |
hex | 1d1d3467af |
125044025263 has 2 divisors, whose sum is σ = 125044025264. Its totient is φ = 125044025262.
The previous prime is 125044025261. The next prime is 125044025339. The reversal of 125044025263 is 362520440521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125044025263 - 21 = 125044025261 is a prime.
It is a super-3 number, since 3×1250440252633 (a number of 34 digits) contains 333 as substring.
Together with 125044025261, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125044025261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62522012631 + 62522012632.
It is an arithmetic number, because the mean of its divisors is an integer number (62522012632).
Almost surely, 2125044025263 is an apocalyptic number.
125044025263 is a deficient number, since it is larger than the sum of its proper divisors (1).
125044025263 is an equidigital number, since it uses as much as digits as its factorization.
125044025263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 125044025263 its reverse (362520440521), we get a palindrome (487564465784).
The spelling of 125044025263 in words is "one hundred twenty-five billion, forty-four million, twenty-five thousand, two hundred sixty-three".
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