1250502532241 has 2 divisors, whose sum is σ = 1250502532242. Its totient is φ = 1250502532240.

The previous prime is 1250502532157. The next prime is 1250502532243. The reversal of 1250502532241 is 1422352050521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1237845382225 + 12657150016 = 1112585^2 + 112504^2 .

It is an emirp because it is prime and its reverse (1422352050521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1250502532241 is a prime.

Together with 1250502532243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1250502532198 and 1250502532207.

It is not a weakly prime, because it can be changed into another prime (1250502532243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625251266120 + 625251266121.

It is an arithmetic number, because the mean of its divisors is an integer number (625251266121).

Almost surely, 2^{1250502532241} is an apocalyptic number.

It is an amenable number.

1250502532241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250502532241 is an equidigital number, since it uses as much as digits as its factorization.

1250502532241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 1250502532241 its reverse (1422352050521), we get a palindrome (2672854582762).

The spelling of 1250502532241 in words is "one trillion, two hundred fifty billion, five hundred two million, five hundred thirty-two thousand, two hundred forty-one".