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1250502532243 is a prime number
BaseRepresentation
bin10010001100100111110…
…000100101110010010011
311102112202200010120020121
4102030213300211302103
5130442012122012433
62354250053051111
7156226422100246
oct22144760456223
94375680116217
101250502532243
11442376096048
12182432926a97
1390bca4b8293
144474b8ad25d
15227dd748c2d
hex12327c25c93

1250502532243 has 2 divisors, whose sum is σ = 1250502532244. Its totient is φ = 1250502532242.

The previous prime is 1250502532241. The next prime is 1250502532271. The reversal of 1250502532243 is 3422352050521.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1250502532243 - 21 = 1250502532241 is a prime.

It is a super-2 number, since 2×12505025322432 (a number of 25 digits) contains 22 as substring.

Together with 1250502532241, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1250502532199 and 1250502532208.

It is not a weakly prime, because it can be changed into another prime (1250502532241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625251266121 + 625251266122.

It is an arithmetic number, because the mean of its divisors is an integer number (625251266122).

Almost surely, 21250502532243 is an apocalyptic number.

1250502532243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250502532243 is an equidigital number, since it uses as much as digits as its factorization.

1250502532243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 1250502532243 its reverse (3422352050521), we get a palindrome (4672854582764).

The spelling of 1250502532243 in words is "one trillion, two hundred fifty billion, five hundred two million, five hundred thirty-two thousand, two hundred forty-three".