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125113450005 = 3253172387643
BaseRepresentation
bin111010010000101010…
…1111011111000010101
3102221221101000210012200
41310201111323320111
54022213020400010
6133250515235113
712016266530625
oct1644125737025
9387841023180
10125113450005
114907330a865
12202b82a8a99
13ba4b6b872b
1460ac4da885
1533c3d6bcc0
hex1d2157be15

125113450005 has 24 divisors (see below), whose sum is σ = 216872623968. Its totient is φ = 66724308576.

The previous prime is 125113449983. The next prime is 125113450043. The reversal of 125113450005 is 500054311521.

125113450005 is a `hidden beast` number, since 1 + 25 + 1 + 134 + 500 + 0 + 5 = 666.

It is not a de Polignac number, because 125113450005 - 25 = 125113449973 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1383714 + ... + 1471356.

It is an arithmetic number, because the mean of its divisors is an integer number (9036359332).

Almost surely, 2125113450005 is an apocalyptic number.

125113450005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

125113450005 is a deficient number, since it is larger than the sum of its proper divisors (91759173963).

125113450005 is a wasteful number, since it uses less digits than its factorization.

125113450005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119377 (or 119374 counting only the distinct ones).

The product of its (nonzero) digits is 3000, while the sum is 27.

Adding to 125113450005 its reverse (500054311521), we get a palindrome (625167761526).

The spelling of 125113450005 in words is "one hundred twenty-five billion, one hundred thirteen million, four hundred fifty thousand, five".

Divisors: 1 3 5 9 15 45 31723 87643 95169 158615 262929 285507 438215 475845 788787 1314645 1427535 3943935 2780298889 8340896667 13901494445 25022690001 41704483335 125113450005