Base | Representation |
---|---|
bin | 111010010000101010… |
… | …1111011111000010101 |
3 | 102221221101000210012200 |
4 | 1310201111323320111 |
5 | 4022213020400010 |
6 | 133250515235113 |
7 | 12016266530625 |
oct | 1644125737025 |
9 | 387841023180 |
10 | 125113450005 |
11 | 4907330a865 |
12 | 202b82a8a99 |
13 | ba4b6b872b |
14 | 60ac4da885 |
15 | 33c3d6bcc0 |
hex | 1d2157be15 |
125113450005 has 24 divisors (see below), whose sum is σ = 216872623968. Its totient is φ = 66724308576.
The previous prime is 125113449983. The next prime is 125113450043. The reversal of 125113450005 is 500054311521.
125113450005 is a `hidden beast` number, since 1 + 25 + 1 + 134 + 500 + 0 + 5 = 666.
It is not a de Polignac number, because 125113450005 - 25 = 125113449973 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1383714 + ... + 1471356.
It is an arithmetic number, because the mean of its divisors is an integer number (9036359332).
Almost surely, 2125113450005 is an apocalyptic number.
125113450005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
125113450005 is a deficient number, since it is larger than the sum of its proper divisors (91759173963).
125113450005 is a wasteful number, since it uses less digits than its factorization.
125113450005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 119377 (or 119374 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 125113450005 its reverse (500054311521), we get a palindrome (625167761526).
The spelling of 125113450005 in words is "one hundred twenty-five billion, one hundred thirteen million, four hundred fifty thousand, five".
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