Base | Representation |
---|---|
bin | 10111010011011101… |
… | …11111101100101101 |
3 | 1012021221022012102221 |
4 | 23221232333230231 |
5 | 201110401023303 |
6 | 5425253315341 |
7 | 622020452545 |
oct | 135156775455 |
9 | 35257265387 |
10 | 12511345453 |
11 | 5340368022 |
12 | 2512035b51 |
13 | 124508c9b9 |
14 | 8698c8325 |
15 | 4d35ca4bd |
hex | 2e9bbfb2d |
12511345453 has 2 divisors, whose sum is σ = 12511345454. Its totient is φ = 12511345452.
The previous prime is 12511345417. The next prime is 12511345463. The reversal of 12511345453 is 35454311521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10099848004 + 2411497449 = 100498^2 + 49107^2 .
It is a cyclic number.
It is not a de Polignac number, because 12511345453 - 213 = 12511337261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12511345463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255672726 + 6255672727.
It is an arithmetic number, because the mean of its divisors is an integer number (6255672727).
Almost surely, 212511345453 is an apocalyptic number.
It is an amenable number.
12511345453 is a deficient number, since it is larger than the sum of its proper divisors (1).
12511345453 is an equidigital number, since it uses as much as digits as its factorization.
12511345453 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36000, while the sum is 34.
Adding to 12511345453 its reverse (35454311521), we get a palindrome (47965656974).
The spelling of 12511345453 in words is "twelve billion, five hundred eleven million, three hundred forty-five thousand, four hundred fifty-three".
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