Base | Representation |
---|---|
bin | 1110111010100… |
… | …11000101111101 |
3 | 22201102210121011 |
4 | 13131103011331 |
5 | 224012332033 |
6 | 20225435221 |
7 | 3046336642 |
oct | 735230575 |
9 | 281383534 |
10 | 125120893 |
11 | 6469a1a7 |
12 | 35a9bb11 |
13 | 1cbcaa41 |
14 | 1288ddc9 |
15 | aeb7ccd |
hex | 775317d |
125120893 has 2 divisors, whose sum is σ = 125120894. Its totient is φ = 125120892.
The previous prime is 125120881. The next prime is 125120899. The reversal of 125120893 is 398021521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89813529 + 35307364 = 9477^2 + 5942^2 .
It is a cyclic number.
It is not a de Polignac number, because 125120893 - 25 = 125120861 is a prime.
It is equal to p7116592 and since 125120893 and 7116592 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125120899) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62560446 + 62560447.
It is an arithmetic number, because the mean of its divisors is an integer number (62560447).
Almost surely, 2125120893 is an apocalyptic number.
It is an amenable number.
125120893 is a deficient number, since it is larger than the sum of its proper divisors (1).
125120893 is an equidigital number, since it uses as much as digits as its factorization.
125120893 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 31.
The square root of 125120893 is about 11185.7450802349. The cubic root of 125120893 is about 500.1611387297.
The spelling of 125120893 in words is "one hundred twenty-five million, one hundred twenty thousand, eight hundred ninety-three".
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