Base | Representation |
---|---|
bin | 1011011000010011111101… |
… | …0100011001001111110111 |
3 | 1122022011102211202102001211 |
4 | 2312010333110121033313 |
5 | 3120000143310403101 |
6 | 42340023332502251 |
7 | 2430661336360660 |
oct | 266047724311767 |
9 | 48264384672054 |
10 | 12512302044151 |
11 | 3a9448a344138 |
12 | 14a0b7477a987 |
13 | 6c9b9c437510 |
14 | 3138549a6367 |
15 | 16a718a88c51 |
hex | b613f5193f7 |
12512302044151 has 32 divisors (see below), whose sum is σ = 16305987277440. Its totient is φ = 9317292281856.
The previous prime is 12512302044139. The next prime is 12512302044233. The reversal of 12512302044151 is 15144020321521.
It is not a de Polignac number, because 12512302044151 - 215 = 12512302011383 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12512302045151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 133733155 + ... + 133826683.
It is an arithmetic number, because the mean of its divisors is an integer number (509562102420).
Almost surely, 212512302044151 is an apocalyptic number.
12512302044151 is a deficient number, since it is larger than the sum of its proper divisors (3793685233289).
12512302044151 is a wasteful number, since it uses less digits than its factorization.
12512302044151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 180043.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 12512302044151 its reverse (15144020321521), we get a palindrome (27656322365672).
The spelling of 12512302044151 in words is "twelve trillion, five hundred twelve billion, three hundred two million, forty-four thousand, one hundred fifty-one".
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