Base | Representation |
---|---|
bin | 10111010011110001… |
… | …01001100010010101 |
3 | 1012022010001202212020 |
4 | 23221320221202111 |
5 | 201112023013432 |
6 | 5425423443353 |
7 | 622051122561 |
oct | 135170514225 |
9 | 35263052766 |
10 | 12513876117 |
11 | 5341836386 |
12 | 2512a56559 |
13 | 1245767832 |
14 | 869d866a1 |
15 | 4d392a22c |
hex | 2e9e29895 |
12513876117 has 4 divisors (see below), whose sum is σ = 16685168160. Its totient is φ = 8342584076.
The previous prime is 12513876073. The next prime is 12513876139. The reversal of 12513876117 is 71167831521.
12513876117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12513876117 - 216 = 12513810581 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12513876517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2085646017 + ... + 2085646022.
It is an arithmetic number, because the mean of its divisors is an integer number (4171292040).
Almost surely, 212513876117 is an apocalyptic number.
It is an amenable number.
12513876117 is a deficient number, since it is larger than the sum of its proper divisors (4171292043).
12513876117 is an equidigital number, since it uses as much as digits as its factorization.
12513876117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4171292042.
The product of its digits is 70560, while the sum is 42.
The spelling of 12513876117 in words is "twelve billion, five hundred thirteen million, eight hundred seventy-six thousand, one hundred seventeen".
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