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12513890151461 is a prime number
BaseRepresentation
bin1011011000011001110111…
…1110100010110000100101
31122022022112112001121202002
42312012131332202300211
53120011421334321321
642340445103255045
72431045602146306
oct266063576426045
948268475047662
1012513890151461
113a95124832716
1214a13385aa485
136ca09346809a
143139658827ad
1516a7ad1d920b
hexb619dfa2c25

12513890151461 has 2 divisors, whose sum is σ = 12513890151462. Its totient is φ = 12513890151460.

The previous prime is 12513890151383. The next prime is 12513890151533. The reversal of 12513890151461 is 16415109831521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7605427746436 + 4908462405025 = 2757794^2 + 2215505^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12513890151461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12513890153461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256945075730 + 6256945075731.

It is an arithmetic number, because the mean of its divisors is an integer number (6256945075731).

Almost surely, 212513890151461 is an apocalyptic number.

It is an amenable number.

12513890151461 is a deficient number, since it is larger than the sum of its proper divisors (1).

12513890151461 is an equidigital number, since it uses as much as digits as its factorization.

12513890151461 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 47.

Adding to 12513890151461 its reverse (16415109831521), we get a palindrome (28928999982982).

The spelling of 12513890151461 in words is "twelve trillion, five hundred thirteen billion, eight hundred ninety million, one hundred fifty-one thousand, four hundred sixty-one".