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125140117 = 642719471
BaseRepresentation
bin1110111010101…
…11110010010101
322201110202222011
413131113302111
5224013440432
620230104221
73046446664
oct735276225
9281422864
10125140117
1164702693
1235aab071
131cc0670b
1412896ddb
15aebd847
hex7757c95

125140117 has 4 divisors (see below), whose sum is σ = 125166016. Its totient is φ = 125114220.

The previous prime is 125140109. The next prime is 125140123. The reversal of 125140117 is 711041521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 125140117 - 23 = 125140109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125146117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3309 + ... + 16162.

It is an arithmetic number, because the mean of its divisors is an integer number (31291504).

Almost surely, 2125140117 is an apocalyptic number.

It is an amenable number.

125140117 is a deficient number, since it is larger than the sum of its proper divisors (25899).

125140117 is an equidigital number, since it uses as much as digits as its factorization.

125140117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25898.

The product of its (nonzero) digits is 280, while the sum is 22.

The square root of 125140117 is about 11186.6043552099. The cubic root of 125140117 is about 500.1867529047.

Adding to 125140117 its reverse (711041521), we get a palindrome (836181638).

The spelling of 125140117 in words is "one hundred twenty-five million, one hundred forty thousand, one hundred seventeen".

Divisors: 1 6427 19471 125140117