Base | Representation |
---|---|
bin | 10010001101011110100… |
… | …000010101001111000111 |
3 | 11102122010200102102111201 |
4 | 102031132200111033013 |
5 | 131000402240021111 |
6 | 2354521143243331 |
7 | 156261244064413 |
oct | 22153640251707 |
9 | 4378120372451 |
10 | 1251421017031 |
11 | 4427a75a3289 |
12 | 18264a449547 |
13 | 910158844c3 |
14 | 447d787bd43 |
15 | 228441c76c1 |
hex | 1235e8153c7 |
1251421017031 has 2 divisors, whose sum is σ = 1251421017032. Its totient is φ = 1251421017030.
The previous prime is 1251421017029. The next prime is 1251421017053. The reversal of 1251421017031 is 1307101241521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1251421017031 - 21 = 1251421017029 is a prime.
It is a super-2 number, since 2×12514210170312 (a number of 25 digits) contains 22 as substring.
Together with 1251421017029, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1251421017061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625710508515 + 625710508516.
It is an arithmetic number, because the mean of its divisors is an integer number (625710508516).
Almost surely, 21251421017031 is an apocalyptic number.
1251421017031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1251421017031 is an equidigital number, since it uses as much as digits as its factorization.
1251421017031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 28.
Adding to 1251421017031 its reverse (1307101241521), we get a palindrome (2558522258552).
The spelling of 1251421017031 in words is "one trillion, two hundred fifty-one billion, four hundred twenty-one million, seventeen thousand, thirty-one".
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