Base | Representation |
---|---|
bin | 1011011000011011001011… |
… | …1101111010111111110010 |
3 | 1122022100110001201010121202 |
4 | 2312012302331322333302 |
5 | 3120013132012411010 |
6 | 42340544043251202 |
7 | 2431060406354051 |
oct | 266066275727762 |
9 | 48270401633552 |
10 | 12514242310130 |
11 | 3a952955a1740 |
12 | 14a1416519b02 |
13 | 6ca11b3c89b2 |
14 | 31399a552398 |
15 | 16a7ce09c6a5 |
hex | b61b2f7aff2 |
12514242310130 has 64 divisors (see below), whose sum is σ = 24594283808640. Its totient is φ = 4546771891200.
The previous prime is 12514242310117. The next prime is 12514242310139. The reversal of 12514242310130 is 3101324241521.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 12514242310093 and 12514242310102.
It is not an unprimeable number, because it can be changed into a prime (12514242310139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 755637050 + ... + 755653610.
It is an arithmetic number, because the mean of its divisors is an integer number (384285684510).
Almost surely, 212514242310130 is an apocalyptic number.
12514242310130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12514242310130 is a deficient number, since it is larger than the sum of its proper divisors (12080041498510).
12514242310130 is a wasteful number, since it uses less digits than its factorization.
12514242310130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21995.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 12514242310130 its reverse (3101324241521), we get a palindrome (15615566551651).
The spelling of 12514242310130 in words is "twelve trillion, five hundred fourteen billion, two hundred forty-two million, three hundred ten thousand, one hundred thirty".
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