Base | Representation |
---|---|
bin | 111010010001111000… |
… | …0100111110111010111 |
3 | 102222001012022221211001 |
4 | 1310203300213313113 |
5 | 4022303411002333 |
6 | 133254524324131 |
7 | 12020301310321 |
oct | 1644360476727 |
9 | 388035287731 |
10 | 125154000343 |
11 | 49094196939 |
12 | 203099a3647 |
13 | ba56c15908 |
14 | 60b3a54611 |
15 | 33c76cbb7d |
hex | 1d23c27dd7 |
125154000343 has 2 divisors, whose sum is σ = 125154000344. Its totient is φ = 125154000342.
The previous prime is 125154000341. The next prime is 125154000359. The reversal of 125154000343 is 343000451521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 125154000343 - 21 = 125154000341 is a prime.
Together with 125154000341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125154000341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62577000171 + 62577000172.
It is an arithmetic number, because the mean of its divisors is an integer number (62577000172).
Almost surely, 2125154000343 is an apocalyptic number.
125154000343 is a deficient number, since it is larger than the sum of its proper divisors (1).
125154000343 is an equidigital number, since it uses as much as digits as its factorization.
125154000343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 125154000343 its reverse (343000451521), we get a palindrome (468154451864).
The spelling of 125154000343 in words is "one hundred twenty-five billion, one hundred fifty-four million, three hundred forty-three", and thus it is an aban number.
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