Base | Representation |
---|---|
bin | 10111010100001001… |
… | …10000011001111111 |
3 | 1012022100001000120211 |
4 | 23222010300121333 |
5 | 201113331044413 |
6 | 5430015453251 |
7 | 622120112044 |
oct | 135204603177 |
9 | 35270030524 |
10 | 12517049983 |
11 | 5343603a09 |
12 | 2513b27227 |
13 | 1246309369 |
14 | 86a5711cb |
15 | 4d3d5583d |
hex | 2ea13067f |
12517049983 has 2 divisors, whose sum is σ = 12517049984. Its totient is φ = 12517049982.
The previous prime is 12517049911. The next prime is 12517050019. The reversal of 12517049983 is 38994071521.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12517049983 - 29 = 12517049471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12517049183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6258524991 + 6258524992.
It is an arithmetic number, because the mean of its divisors is an integer number (6258524992).
Almost surely, 212517049983 is an apocalyptic number.
12517049983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12517049983 is an equidigital number, since it uses as much as digits as its factorization.
12517049983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 49.
The spelling of 12517049983 in words is "twelve billion, five hundred seventeen million, forty-nine thousand, nine hundred eighty-three".
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