Search a number
-
+
12517806793 is a prime number
BaseRepresentation
bin10111010100001111…
…01001001011001001
31012022101110110201211
423222013221023021
5201114024304133
65430044013121
7622126413352
oct135207511311
935271413654
1012517806793
115343a80578
1225142311a1
13124651298b
1486a6cad29
154d3e54bcd
hex2ea1e92c9

12517806793 has 2 divisors, whose sum is σ = 12517806794. Its totient is φ = 12517806792.

The previous prime is 12517806773. The next prime is 12517806797. The reversal of 12517806793 is 39760871521.

It is a happy number.

12517806793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9106312329 + 3411494464 = 95427^2 + 58408^2 .

It is a cyclic number.

It is not a de Polignac number, because 12517806793 - 221 = 12515709641 is a prime.

It is not a weakly prime, because it can be changed into another prime (12517806797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6258903396 + 6258903397.

It is an arithmetic number, because the mean of its divisors is an integer number (6258903397).

Almost surely, 212517806793 is an apocalyptic number.

It is an amenable number.

12517806793 is a deficient number, since it is larger than the sum of its proper divisors (1).

12517806793 is an equidigital number, since it uses as much as digits as its factorization.

12517806793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 635040, while the sum is 49.

The spelling of 12517806793 in words is "twelve billion, five hundred seventeen million, eight hundred six thousand, seven hundred ninety-three".