12520325112041 has 8 divisors (see below), whose sum is σ = 13256948582280. Its totient is φ = 11783716503808.

The previous prime is 12520325111971. The next prime is 12520325112059. The reversal of 12520325112041 is 14021152302521.

It can be written as a sum of positive squares in 4 ways, for example, as 3589963878400 + 8930361233641 = 1894720^2 + 2988371^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12520325112041 is a prime.

It is a super-2 number, since 2×12520325112041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12520325111995 and 12520325112013.

It is not an unprimeable number, because it can be changed into a prime (12520325112241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1957286 + ... + 5373231.

It is an arithmetic number, because the mean of its divisors is an integer number (1657118572785).

Almost surely, 2^{12520325112041} is an apocalyptic number.

It is an amenable number.

12520325112041 is a deficient number, since it is larger than the sum of its proper divisors (736623470239).

12520325112041 is a wasteful number, since it uses less digits than its factorization.

12520325112041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7431003.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 12520325112041 its reverse (14021152302521), we get a palindrome (26541477414562).

The spelling of 12520325112041 in words is "twelve trillion, five hundred twenty billion, three hundred twenty-five million, one hundred twelve thousand, forty-one".