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125210051 is a prime number
BaseRepresentation
bin1110111011010…
…00110111000011
322201121022220022
413131220313003
5224023210201
620231404055
73050160611
oct735506703
9281538808
10125210051
116475018a
1235b2362b
131cc2c4b5
14128b46b1
15aed441b
hex7768dc3

125210051 has 2 divisors, whose sum is σ = 125210052. Its totient is φ = 125210050.

The previous prime is 125210047. The next prime is 125210053. The reversal of 125210051 is 150012521.

It is a strong prime.

It is an emirp because it is prime and its reverse (150012521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125210051 - 22 = 125210047 is a prime.

Together with 125210053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (125210053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62605025 + 62605026.

It is an arithmetic number, because the mean of its divisors is an integer number (62605026).

Almost surely, 2125210051 is an apocalyptic number.

125210051 is a deficient number, since it is larger than the sum of its proper divisors (1).

125210051 is an equidigital number, since it uses as much as digits as its factorization.

125210051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100, while the sum is 17.

The square root of 125210051 is about 11189.7297107660. The cubic root of 125210051 is about 500.2799112701.

Adding to 125210051 its reverse (150012521), we get a palindrome (275222572).

The spelling of 125210051 in words is "one hundred twenty-five million, two hundred ten thousand, fifty-one".