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125215124350400 = 2652720849536233
BaseRepresentation
bin11100011110000111101011…
…000000011110010111000000
3121102100110010022022110012222
4130132013223000132113000
5112403011033313203100
61122151011202510212
735242331336563340
oct3436075300362700
9542313108273188
10125215124350400
1136996488387207
1212063643965368
1354b3974047266
1422cc63144ad20
15e721ecec5485
hex71e1eb01e5c0

125215124350400 has 168 divisors, whose sum is σ = 352140363434400. Its totient is φ = 42928760586240.

The previous prime is 125215124350399. The next prime is 125215124350417. The reversal of 125215124350400 is 4053421512521.

125215124350400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1252151243504002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 233240684 + ... + 233776916.

Almost surely, 2125215124350400 is an apocalyptic number.

125215124350400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 125215124350400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176070181717200).

125215124350400 is an abundant number, since it is smaller than the sum of its proper divisors (226925239084000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125215124350400 is a wasteful number, since it uses less digits than its factorization.

125215124350400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 557111 (or 557096 counting only the distinct ones).

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 125215124350400 its reverse (4053421512521), we get a palindrome (129268545862921).

The spelling of 125215124350400 in words is "one hundred twenty-five trillion, two hundred fifteen billion, one hundred twenty-four million, three hundred fifty thousand, four hundred".