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1252212581117 is a prime number
BaseRepresentation
bin10010001110001101101…
…011111010001011111101
311102201011211220001022002
4102032031223322023331
5131004012410043432
62355131501232045
7156316665214421
oct22161553721375
94381154801262
101252212581117
114430733a2083
1218282b562625
1391110872714
1444870a4cb81
152288d934e62
hex1238dafa2fd

1252212581117 has 2 divisors, whose sum is σ = 1252212581118. Its totient is φ = 1252212581116.

The previous prime is 1252212581057. The next prime is 1252212581119. The reversal of 1252212581117 is 7111852122521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1010469258841 + 241743322276 = 1005221^2 + 491674^2 .

It is an emirp because it is prime and its reverse (7111852122521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1252212581117 - 220 = 1252211532541 is a prime.

Together with 1252212581119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1252212581119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626106290558 + 626106290559.

It is an arithmetic number, because the mean of its divisors is an integer number (626106290559).

Almost surely, 21252212581117 is an apocalyptic number.

It is an amenable number.

1252212581117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252212581117 is an equidigital number, since it uses as much as digits as its factorization.

1252212581117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 22400, while the sum is 38.

The spelling of 1252212581117 in words is "one trillion, two hundred fifty-two billion, two hundred twelve million, five hundred eighty-one thousand, one hundred seventeen".