12523151129 has 2 divisors, whose sum is σ = 12523151130. Its totient is φ = 12523151128.

The previous prime is 12523151119. The next prime is 12523151131. The reversal of 12523151129 is 92115132521.

12523151129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8050216729 + 4472934400 = 89723^2 + 66880^2 .

It is a cyclic number.

It is not a de Polignac number, because 12523151129 - 2¹² = 12523147033 is a prime.

Together with 12523151131, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12523151095 and 12523151104.

It is not a weakly prime, because it can be changed into another prime (12523151119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6261575564 + 6261575565.

It is an arithmetic number, because the mean of its divisors is an integer number (6261575565).

Almost surely, 2^12523151129 is an apocalyptic number.

It is an amenable number.

12523151129 is a deficient number, since it is larger than the sum of its proper divisors (1).

12523151129 is an equidigital number, since it uses as much as digits as its factorization.

12523151129 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 32.

The spelling of 12523151129 in words is "twelve billion, five hundred twenty-three million, one hundred fifty-one thousand, one hundred twenty-nine".