1252413000040 has 128 divisors (see below), whose sum is σ = 2852909579520. Its totient is φ = 494796902400.

The previous prime is 1252412999989. The next prime is 1252413000043. The reversal of 1252413000040 is 400003142521.

It is a junction number, because it is equal to n+sod(n) for n = 1252412999975 and 1252413000020.

It is not an unprimeable number, because it can be changed into a prime (1252413000043) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 877653807 + ... + 877655233.

It is an arithmetic number, because the mean of its divisors is an integer number (22288356090).

Almost surely, 2^{1252413000040} is an apocalyptic number.

1252413000040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1252413000040 is an abundant number, since it is smaller than the sum of its proper divisors (1600496579480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1252413000040 is a wasteful number, since it uses less digits than its factorization.

1252413000040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2363 (or 2359 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 22.

Adding to 1252413000040 its reverse (400003142521), we get a palindrome (1652416142561).

The spelling of 1252413000040 in words is "one trillion, two hundred fifty-two billion, four hundred thirteen million, forty", and thus it is an aban number.