Base | Representation |
---|---|
bin | 1011011001010101111101… |
… | …1010100111001011111111 |
3 | 1122100212011122222212102211 |
4 | 2312111133122213023333 |
5 | 3120242440211223312 |
6 | 42352113435001251 |
7 | 2432156405133352 |
oct | 266253732471377 |
9 | 48325148885384 |
10 | 12530020414207 |
11 | 3aa0a5195987a |
12 | 14a449a599227 |
13 | 6cb7641cc55a |
14 | 314655c42299 |
15 | 16ae043613a7 |
hex | b655f6a72ff |
12530020414207 has 2 divisors, whose sum is σ = 12530020414208. Its totient is φ = 12530020414206.
The previous prime is 12530020414201. The next prime is 12530020414231. The reversal of 12530020414207 is 70241402003521.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12530020414207 - 211 = 12530020412159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12530020414201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265010207103 + 6265010207104.
It is an arithmetic number, because the mean of its divisors is an integer number (6265010207104).
Almost surely, 212530020414207 is an apocalyptic number.
12530020414207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12530020414207 is an equidigital number, since it uses as much as digits as its factorization.
12530020414207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 12530020414207 its reverse (70241402003521), we get a palindrome (82771422417728).
The spelling of 12530020414207 in words is "twelve trillion, five hundred thirty billion, twenty million, four hundred fourteen thousand, two hundred seven".
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