Base | Representation |
---|---|
bin | 1011011001011000000110… |
… | …1111011100001010001111 |
3 | 1122100220122210121212102022 |
4 | 2312112001233130022033 |
5 | 3120300130123040112 |
6 | 42352250530120355 |
7 | 2432206600105064 |
oct | 266260157341217 |
9 | 48326583555368 |
10 | 12530596299407 |
11 | 3aa1217a3695a |
12 | 14a461b4200bb |
13 | 6cb826603b24 |
14 | 3146ac50cc6b |
15 | 16ae39bb8d72 |
hex | b6581bdc28f |
12530596299407 has 2 divisors, whose sum is σ = 12530596299408. Its totient is φ = 12530596299406.
The previous prime is 12530596299401. The next prime is 12530596299421. The reversal of 12530596299407 is 70499269503521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12530596299407 - 212 = 12530596295311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12530596299407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12530596299401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265298149703 + 6265298149704.
It is an arithmetic number, because the mean of its divisors is an integer number (6265298149704).
Almost surely, 212530596299407 is an apocalyptic number.
12530596299407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12530596299407 is an equidigital number, since it uses as much as digits as its factorization.
12530596299407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36741600, while the sum is 62.
The spelling of 12530596299407 in words is "twelve trillion, five hundred thirty billion, five hundred ninety-six million, two hundred ninety-nine thousand, four hundred seven".
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