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125313161070389 is a prime number
BaseRepresentation
bin11100011111100010111110…
…011100111000011100110101
3121102200211011122200211121012
4130133202332130320130311
5112411112323213223024
61122304023234002005
735252401644134405
oct3437427634703465
9542624148624535
10125313161070389
1136a24016575a46
121207a644116305
1354bcc98b98246
1422d3291850805
15e74a39ba250e
hex71f8be738735

125313161070389 has 2 divisors, whose sum is σ = 125313161070390. Its totient is φ = 125313161070388.

The previous prime is 125313161070347. The next prime is 125313161070469. The reversal of 125313161070389 is 983070161313521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124545376800100 + 767784270289 = 11159990^2 + 876233^2 .

It is a cyclic number.

It is not a de Polignac number, because 125313161070389 - 224 = 125313144293173 is a prime.

It is a super-2 number, since 2×1253131610703892 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125313161070689) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62656580535194 + 62656580535195.

It is an arithmetic number, because the mean of its divisors is an integer number (62656580535195).

Almost surely, 2125313161070389 is an apocalyptic number.

It is an amenable number.

125313161070389 is a deficient number, since it is larger than the sum of its proper divisors (1).

125313161070389 is an equidigital number, since it uses as much as digits as its factorization.

125313161070389 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 816480, while the sum is 50.

The spelling of 125313161070389 in words is "one hundred twenty-five trillion, three hundred thirteen billion, one hundred sixty-one million, seventy thousand, three hundred eighty-nine".