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125313161070469 is a prime number
BaseRepresentation
bin11100011111100010111110…
…011100111000011110000101
3121102200211011122200211201011
4130133202332130320132011
5112411112323213223334
61122304023234002221
735252401644134551
oct3437427634703605
9542624148624634
10125313161070469
1136a24016576009
121207a644116371
1354bcc98b982a8
1422d3291850861
15e74a39ba2564
hex71f8be738785

125313161070469 has 2 divisors, whose sum is σ = 125313161070470. Its totient is φ = 125313161070468.

The previous prime is 125313161070389. The next prime is 125313161070491. The reversal of 125313161070469 is 964070161313521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90092615674369 + 35220545396100 = 9491713^2 + 5934690^2 .

It is a cyclic number.

It is not a de Polignac number, because 125313161070469 - 27 = 125313161070341 is a prime.

It is a super-2 number, since 2×1253131610704692 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125313161070169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62656580535234 + 62656580535235.

It is an arithmetic number, because the mean of its divisors is an integer number (62656580535235).

Almost surely, 2125313161070469 is an apocalyptic number.

It is an amenable number.

125313161070469 is a deficient number, since it is larger than the sum of its proper divisors (1).

125313161070469 is an equidigital number, since it uses as much as digits as its factorization.

125313161070469 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 816480, while the sum is 49.

The spelling of 125313161070469 in words is "one hundred twenty-five trillion, three hundred thirteen billion, one hundred sixty-one million, seventy thousand, four hundred sixty-nine".