Base | Representation |
---|---|
bin | 10010001111000101111… |
… | …000100010010100001111 |
3 | 11102210121112222222200001 |
4 | 102033011320202110033 |
5 | 131012430241242221 |
6 | 2355405221345131 |
7 | 156352234164232 |
oct | 22170570422417 |
9 | 4383545888601 |
10 | 1253155415311 |
11 | 443507620398 |
12 | 182a532681a7 |
13 | 91230cb5987 |
14 | 4491dd59419 |
15 | 228e65c3391 |
hex | 123c5e2250f |
1253155415311 has 4 divisors (see below), whose sum is σ = 1307640433392. Its totient is φ = 1198670397232.
The previous prime is 1253155415251. The next prime is 1253155415353. The reversal of 1253155415311 is 1135145513521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1253155415311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1253155415371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27242509006 + ... + 27242509051.
It is an arithmetic number, because the mean of its divisors is an integer number (326910108348).
Almost surely, 21253155415311 is an apocalyptic number.
1253155415311 is a deficient number, since it is larger than the sum of its proper divisors (54485018081).
1253155415311 is an equidigital number, since it uses as much as digits as its factorization.
1253155415311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54485018080.
The product of its digits is 45000, while the sum is 37.
The spelling of 1253155415311 in words is "one trillion, two hundred fifty-three billion, one hundred fifty-five million, four hundred fifteen thousand, three hundred eleven".
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