12532405113103 has 4 divisors (see below), whose sum is σ = 12532412352160. Its totient is φ = 12532397874048.

The previous prime is 12532405113097. The next prime is 12532405113121. The reversal of 12532405113103 is 30131150423521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12532405113103 - 2²⁵ = 12532371558671 is a prime.

It is a super-2 number, since 2×12532405113103² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12532405113203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 678703 + ... + 5052271.

It is an arithmetic number, because the mean of its divisors is an integer number (3133103088040).

Almost surely, 2^{12532405113103} is an apocalyptic number.

12532405113103 is a deficient number, since it is larger than the sum of its proper divisors (7239057).

12532405113103 is an equidigital number, since it uses as much as digits as its factorization.

12532405113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7239056.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 12532405113103 its reverse (30131150423521), we get a palindrome (42663555536624).

The spelling of 12532405113103 in words is "twelve trillion, five hundred thirty-two billion, four hundred five million, one hundred thirteen thousand, one hundred three".