Base | Representation |
---|---|
bin | 11100011111101101010111… |
… | …000100000001001100011101 |
3 | 121102201212221202000100000002 |
4 | 130133231113010001030131 |
5 | 112411303142204314440 |
6 | 1122313105512144045 |
7 | 35253245160315545 |
oct | 3437552704011435 |
9 | 542655852010002 |
10 | 125324311401245 |
11 | 36a28818651610 |
12 | 12080836398025 |
13 | 54c1054ca9258 |
14 | 22d3a2c694325 |
15 | e74e8da39115 |
hex | 71fb5710131d |
125324311401245 has 32 divisors (see below), whose sum is σ = 168502386585600. Its totient is φ = 88677686615040.
The previous prime is 125324311401169. The next prime is 125324311401253. The reversal of 125324311401245 is 542104113423521.
It is not a de Polignac number, because 125324311401245 - 212 = 125324311397149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125324311401199 and 125324311401208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 45451556 + ... + 48129954.
It is an arithmetic number, because the mean of its divisors is an integer number (5265699580800).
Almost surely, 2125324311401245 is an apocalyptic number.
It is an amenable number.
125324311401245 is a deficient number, since it is larger than the sum of its proper divisors (43178075184355).
125324311401245 is a wasteful number, since it uses less digits than its factorization.
125324311401245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2701445.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 125324311401245 its reverse (542104113423521), we get a palindrome (667428424824766).
The spelling of 125324311401245 in words is "one hundred twenty-five trillion, three hundred twenty-four billion, three hundred eleven million, four hundred one thousand, two hundred forty-five".
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