Base | Representation |
---|---|
bin | 1011011001100001011011… |
… | …0110110111001110000111 |
3 | 1122101011010011002222122221 |
4 | 2312120112312313032013 |
5 | 3120320241100103224 |
6 | 42353343055233211 |
7 | 2432325565455631 |
oct | 266302666671607 |
9 | 48334104088587 |
10 | 12533098050439 |
11 | 3aa229112649a |
12 | 14a4bb9218807 |
13 | 6cbb349c7295 |
14 | 314868897a51 |
15 | 16b03463d6e4 |
hex | b6616db7387 |
12533098050439 has 2 divisors, whose sum is σ = 12533098050440. Its totient is φ = 12533098050438.
The previous prime is 12533098050437. The next prime is 12533098050479. The reversal of 12533098050439 is 93405089033521.
It is a weak prime.
It is an emirp because it is prime and its reverse (93405089033521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12533098050439 - 21 = 12533098050437 is a prime.
Together with 12533098050437, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12533098050433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6266549025219 + 6266549025220.
It is an arithmetic number, because the mean of its divisors is an integer number (6266549025220).
Almost surely, 212533098050439 is an apocalyptic number.
12533098050439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12533098050439 is an equidigital number, since it uses as much as digits as its factorization.
12533098050439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3499200, while the sum is 52.
The spelling of 12533098050439 in words is "twelve trillion, five hundred thirty-three billion, ninety-eight million, fifty thousand, four hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •