Base | Representation |
---|---|
bin | 1011011001100001011011… |
… | …0110111001011010101111 |
3 | 1122101011010011010110000021 |
4 | 2312120112312321122233 |
5 | 3120320241100400224 |
6 | 42353343055343011 |
7 | 2432325565524106 |
oct | 266302666713257 |
9 | 48334104113007 |
10 | 12533098059439 |
11 | 3aa2291132231 |
12 | 14a4bb9221a67 |
13 | 6cbb349cb3c9 |
14 | 31486889b03d |
15 | 16b0346411e4 |
hex | b6616db96af |
12533098059439 has 2 divisors, whose sum is σ = 12533098059440. Its totient is φ = 12533098059438.
The previous prime is 12533098059403. The next prime is 12533098059467. The reversal of 12533098059439 is 93495089033521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12533098059439 - 211 = 12533098057391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12533098050439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6266549029719 + 6266549029720.
It is an arithmetic number, because the mean of its divisors is an integer number (6266549029720).
Almost surely, 212533098059439 is an apocalyptic number.
12533098059439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12533098059439 is an equidigital number, since it uses as much as digits as its factorization.
12533098059439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31492800, while the sum is 61.
The spelling of 12533098059439 in words is "twelve trillion, five hundred thirty-three billion, ninety-eight million, fifty-nine thousand, four hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •