Base | Representation |
---|---|
bin | 111010010111001010… |
… | …1111110100111010101 |
3 | 102222111120110011202022 |
4 | 1310232111332213111 |
5 | 4023134340040023 |
6 | 133324310222525 |
7 | 12024555503504 |
oct | 1645625764725 |
9 | 388446404668 |
10 | 125331565013 |
11 | 491754458a6 |
12 | 20359354a45 |
13 | ba84946175 |
14 | 60cd47683b |
15 | 33d80a37c8 |
hex | 1d2e57e9d5 |
125331565013 has 2 divisors, whose sum is σ = 125331565014. Its totient is φ = 125331565012.
The previous prime is 125331565003. The next prime is 125331565027. The reversal of 125331565013 is 310565133521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 81877244164 + 43454320849 = 286142^2 + 208457^2 .
It is a cyclic number.
It is not a de Polignac number, because 125331565013 - 24 = 125331564997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125331565003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62665782506 + 62665782507.
It is an arithmetic number, because the mean of its divisors is an integer number (62665782507).
Almost surely, 2125331565013 is an apocalyptic number.
It is an amenable number.
125331565013 is a deficient number, since it is larger than the sum of its proper divisors (1).
125331565013 is an equidigital number, since it uses as much as digits as its factorization.
125331565013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 125331565013 its reverse (310565133521), we get a palindrome (435896698534).
The spelling of 125331565013 in words is "one hundred twenty-five billion, three hundred thirty-one million, five hundred sixty-five thousand, thirteen".
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