Base | Representation |
---|---|
bin | 111010010111001100… |
… | …0000111011101110011 |
3 | 102222111121111122200010 |
4 | 1310232120013131303 |
5 | 4023140011004210 |
6 | 133324330230003 |
7 | 12024563326650 |
oct | 1645630073563 |
9 | 388447448603 |
10 | 125332125555 |
11 | 49175798a5a |
12 | 20359585303 |
13 | ba84ab1350 |
14 | 60cd580c27 |
15 | 33d8164920 |
hex | 1d2e607773 |
125332125555 has 128 divisors (see below), whose sum is σ = 251104444416. Its totient is φ = 51971673600.
The previous prime is 125332125553. The next prime is 125332125577. The reversal of 125332125555 is 555521233521.
It is not a de Polignac number, because 125332125555 - 21 = 125332125553 is a prime.
It is a super-2 number, since 2×1253321255552 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (125332125553) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 32076912 + ... + 32080818.
It is an arithmetic number, because the mean of its divisors is an integer number (1961753472).
Almost surely, 2125332125555 is an apocalyptic number.
125332125555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
125332125555 is an abundant number, since it is smaller than the sum of its proper divisors (125772318861).
125332125555 is a wasteful number, since it uses less digits than its factorization.
125332125555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4337.
The product of its digits is 225000, while the sum is 39.
The spelling of 125332125555 in words is "one hundred twenty-five billion, three hundred thirty-two million, one hundred twenty-five thousand, five hundred fifty-five".
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