Base | Representation |
---|---|
bin | 1011011001100010010011… |
… | …1100001111001101100010 |
3 | 1122101011201121201202121211 |
4 | 2312120210330033031202 |
5 | 3120321232042343300 |
6 | 42353422335540334 |
7 | 2432334465060040 |
oct | 266304474171542 |
9 | 48334647652554 |
10 | 12533334340450 |
11 | 3aa23a25456a0 |
12 | 14a506438a6aa |
13 | 6cbb71949561 |
14 | 31488c005390 |
15 | 16b04a2654ba |
hex | b6624f0f362 |
12533334340450 has 96 divisors (see below), whose sum is σ = 29180110353408. Its totient is φ = 3890929800000.
The previous prime is 12533334340369. The next prime is 12533334340481. The reversal of 12533334340450 is 5404343333521.
12533334340450 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5518534 + ... + 7451233.
It is an arithmetic number, because the mean of its divisors is an integer number (303959482848).
Almost surely, 212533334340450 is an apocalyptic number.
12533334340450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12533334340450 is an abundant number, since it is smaller than the sum of its proper divisors (16646776012958).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12533334340450 is a wasteful number, since it uses less digits than its factorization.
12533334340450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12970048 (or 12970043 counting only the distinct ones).
The product of its (nonzero) digits is 777600, while the sum is 40.
Adding to 12533334340450 its reverse (5404343333521), we get a palindrome (17937677673971).
The spelling of 12533334340450 in words is "twelve trillion, five hundred thirty-three billion, three hundred thirty-four million, three hundred forty thousand, four hundred fifty".
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