1253339999 has 2 divisors, whose sum is σ = 1253340000. Its totient is φ = 1253339998.

The previous prime is 1253339981. The next prime is 1253340001. The reversal of 1253339999 is 9999333521.

It is a strong prime.

It is an emirp because it is prime and its reverse (9999333521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1253339999 is a prime.

It is a super-2 number, since 2×1253339999² = 3141722306186640002, which contains 22 as substring.

Together with 1253340001, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1253339999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1253339939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626669999 + 626670000.

It is an arithmetic number, because the mean of its divisors is an integer number (626670000).

Almost surely, 2^1253339999 is an apocalyptic number.

1253339999 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253339999 is an equidigital number, since it uses as much as digits as its factorization.

1253339999 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1771470, while the sum is 53.

The square root of 1253339999 is about 35402.5422674700. The cubic root of 1253339999 is about 1078.1759330348.

The spelling of 1253339999 in words is "one billion, two hundred fifty-three million, three hundred thirty-nine thousand, nine hundred ninety-nine".