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12534103 = 23544961
BaseRepresentation
bin101111110100…
…000101010111
3212120210120001
4233310011113
511202042403
61124352131
7211352401
oct57640527
925523501
1012534103
11709106a
124245647
13279b13a
141943b71
151178c1d
hexbf4157

12534103 has 4 divisors (see below), whose sum is σ = 13079088. Its totient is φ = 11989120.

The previous prime is 12534089. The next prime is 12534107. The reversal of 12534103 is 30143521.

12534103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12534103 - 213 = 12525911 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12534107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272458 + ... + 272503.

It is an arithmetic number, because the mean of its divisors is an integer number (3269772).

Almost surely, 212534103 is an apocalyptic number.

12534103 is a deficient number, since it is larger than the sum of its proper divisors (544985).

12534103 is an equidigital number, since it uses as much as digits as its factorization.

12534103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 544984.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 12534103 is about 3540.3535134221. The cubic root of 12534103 is about 232.2903061724.

Adding to 12534103 its reverse (30143521), we get a palindrome (42677624).

It can be divided in two parts, 1253 and 4103, that added together give a triangular number (5356 = T103).

The spelling of 12534103 in words is "twelve million, five hundred thirty-four thousand, one hundred three".

Divisors: 1 23 544961 12534103