1253421454435 has 4 divisors (see below), whose sum is σ = 1504105745328. Its totient is φ = 1002737163544.

The previous prime is 1253421454423. The next prime is 1253421454469. The reversal of 1253421454435 is 5344541243521.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1253421454435 - 2¹⁹ = 1253420930147 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1253421454391 and 1253421454400.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125342145439 + ... + 125342145448.

It is an arithmetic number, because the mean of its divisors is an integer number (376026436332).

Almost surely, 2^{1253421454435} is an apocalyptic number.

1253421454435 is a deficient number, since it is larger than the sum of its proper divisors (250684290893).

1253421454435 is an equidigital number, since it uses as much as digits as its factorization.

1253421454435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 250684290892.

The product of its digits is 1152000, while the sum is 43.

Adding to 1253421454435 its reverse (5344541243521), we get a palindrome (6597962697956).

The spelling of 1253421454435 in words is "one trillion, two hundred fifty-three billion, four hundred twenty-one million, four hundred fifty-four thousand, four hundred thirty-five".