125344031 has 2 divisors, whose sum is σ = 125344032. Its totient is φ = 125344030.

The previous prime is 125344013. The next prime is 125344057. The reversal of 125344031 is 130443521.

Together with previous prime (125344013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 125344031 - 2¹⁰ = 125343007 is a prime.

It is a super-2 number, since 2×125344031² = 31422252214657922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 125343988 and 125344006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125344001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62672015 + 62672016.

It is an arithmetic number, because the mean of its divisors is an integer number (62672016).

Almost surely, 2^125344031 is an apocalyptic number.

125344031 is a deficient number, since it is larger than the sum of its proper divisors (1).

125344031 is an equidigital number, since it uses as much as digits as its factorization.

125344031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 125344031 is about 11195.7148498879. The cubic root of 125344031 is about 500.4582878162.

Adding to 125344031 its reverse (130443521), we get a palindrome (255787552).

The spelling of 125344031 in words is "one hundred twenty-five million, three hundred forty-four thousand, thirty-one".