Base | Representation |
---|---|
bin | 10010001111101100100… |
… | …010010101111101001111 |
3 | 11102212021202020212200201 |
4 | 102033230202111331033 |
5 | 131020242300041233 |
6 | 2355553425034331 |
7 | 156404300245225 |
oct | 22175442257517 |
9 | 4385252225621 |
10 | 1253803908943 |
11 | 44380a690243 |
12 | 182bb44859a7 |
13 | 91305460111 |
14 | 44982126b15 |
15 | 229334be77d |
hex | 123ec895f4f |
1253803908943 has 2 divisors, whose sum is σ = 1253803908944. Its totient is φ = 1253803908942.
The previous prime is 1253803908937. The next prime is 1253803908971. The reversal of 1253803908943 is 3498093083521.
It is a weak prime.
It is an emirp because it is prime and its reverse (3498093083521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1253803908943 - 225 = 1253770354511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1253803908983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626901954471 + 626901954472.
It is an arithmetic number, because the mean of its divisors is an integer number (626901954472).
Almost surely, 21253803908943 is an apocalyptic number.
1253803908943 is a deficient number, since it is larger than the sum of its proper divisors (1).
1253803908943 is an equidigital number, since it uses as much as digits as its factorization.
1253803908943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5598720, while the sum is 55.
The spelling of 1253803908943 in words is "one trillion, two hundred fifty-three billion, eight hundred three million, nine hundred eight thousand, nine hundred forty-three".
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