Base | Representation |
---|---|
bin | 10010001111110000110… |
… | …110010011111101001010 |
3 | 11102212110210101022101100 |
4 | 102033300312103331022 |
5 | 131020414310034430 |
6 | 2400004531402230 |
7 | 156406136202321 |
oct | 22176066237512 |
9 | 4385423338340 |
10 | 1253876252490 |
11 | 443847501aa4 |
12 | 183014753376 |
13 | 9131743c554 |
14 | 4498b9990b8 |
15 | 22939a0e960 |
hex | 123f0d93f4a |
1253876252490 has 24 divisors (see below), whose sum is σ = 3260078256708. Its totient is φ = 334367000640.
The previous prime is 1253876252471. The next prime is 1253876252569. The reversal of 1253876252490 is 942526783521.
1253876252490 is a `hidden beast` number, since 1 + 2 + 5 + 3 + 8 + 7 + 625 + 2 + 4 + 9 + 0 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 1028092574601 + 225783677889 = 1013949^2 + 475167^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6965979091 + ... + 6965979270.
It is a 1-persistent number, because it is pandigital, but 2⋅1253876252490 = 2507752504980 is not.
Almost surely, 21253876252490 is an apocalyptic number.
1253876252490 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1253876252490 is an abundant number, since it is smaller than the sum of its proper divisors (2006202004218).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1253876252490 is a wasteful number, since it uses less digits than its factorization.
1253876252490 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13931958374 (or 13931958371 counting only the distinct ones).
The product of its (nonzero) digits is 7257600, while the sum is 54.
The spelling of 1253876252490 in words is "one trillion, two hundred fifty-three billion, eight hundred seventy-six million, two hundred fifty-two thousand, four hundred ninety".
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