125400047 has 2 divisors, whose sum is σ = 125400048. Its totient is φ = 125400046.

The previous prime is 125400029. The next prime is 125400151. The reversal of 125400047 is 740004521.

It is a weak prime.

It is an emirp because it is prime and its reverse (740004521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125400047 - 2¹⁶ = 125334511 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 125399995 and 125400031.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125400647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62700023 + 62700024.

It is an arithmetic number, because the mean of its divisors is an integer number (62700024).

Almost surely, 2^125400047 is an apocalyptic number.

125400047 is a deficient number, since it is larger than the sum of its proper divisors (1).

125400047 is an equidigital number, since it uses as much as digits as its factorization.

125400047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1120, while the sum is 23.

The square root of 125400047 is about 11198.2162418842. The cubic root of 125400047 is about 500.5328279870.

Adding to 125400047 its reverse (740004521), we get a palindrome (865404568).

The spelling of 125400047 in words is "one hundred twenty-five million, four hundred thousand, forty-seven".